**Q1. **A student obtained 62.5 % marks in a certain examination. If the maximum marks are 800. Find the total marks obtained by her.

A. 525

B. 600

C. 375

D. 500

**Sol: Option D**

**Solution: **800 * 62.5/100 = 500

**Q2. **The annual sales of company B were Rs 96,000 in fiscal year 95-96 and Rs 1,08,000 in fiscal 96-97. What was the % increase in turnover?

A. 16.67 %

B. 62.5 %

C. 40 %

D. 12.5 %

**Sol: Option D**

**Solution: **Increase = 96,000 – 1,08, 000 = 12,000

∴ % Increase = 12000 * 100/96000 = 100 * 1/8 = 12.5 %

**Q3. **The price of a Bajaj Scooter is Rs 25,000 which is 20 % lesser than a LML Scooter. What is the price of a LML Scooter?

A. 15250

B. 31250

C. 40150

D. 75230

**Sol: Option B**

**Solution: **Here note that the % given is defined in terms of the price of LML Scooter and not Bajaj Scooter. ∴ Computing the price of SMS as 1.2 times Bajaj's price will give incorrect answer. The data given is:

LML * (100 – 20)/100 = Bajaj = 25,000

∴ LML =25,000 × 100/80 = Rs 31,250

Or you can simply do = 25,000/0.8 = 31250

(20 % less means it is 0.80 times of the other one)

**Q4. **The price of rice increases by 30 %. In order to keep the expenses on rice constant as before, by what percentage should a person cut down his consumption?

A. 22/3 %

B. 31/5 %

C. 300/13 %

D. 23/11 %

**Sol: Option C**

**Solution: **Applying the formula 100 × R/ (100 + R),
Since the price has increased, the consumption should be reduced by:

(100 × 30)/ (100+30) = 23 1/13 % = 300/13 %. Hence option C

**Q5. **Tom’s income is 20 % less than Jerry’s. How much is Jerry’s income more than Tom’s?

A. 25 %

B. 60 %

C. 45 %

D. 30 %

**Sol: Option A**

**Solution: **Applying the formula 100 * R/(100 - R)

As , income is 20% less

Jerry’s income is more by = 100 * 20/80 = 25 %

Must Read Percentages Articles

**Q6. **A traveling salesman carried 75 % of his money in traveler’s cheque and 25 % in cash. During one of his journeys, he lost his entire cash and spent from his traveler’s cheque. On completion of the journey, he returned 30% of the traveler’s cheque, which amounted to Rs 180. What was the total money that he carried?

A. Rs 500

B. Rs 600

C. Rs 450

D. Rs 800

**Sol: Option D**

**Solution: **30 % of Traveler’s Cheque = Rs 180

∴ 100 % of Traveler's Cheque = 180 * 100/30 = Rs 600

Since Traveler's Cheque accounted for 75% of the total money that he had carried, the total money that he carried is: 600 * 100/75 = Rs 800

**Q7. **A number is increased by 20%, and then it is decreased by 30%, what is the net change in the number?

A. 16 % increase

B. 16 % decrease

C. 10 % decrease

D. 5 % increase

**Sol: Option B**

**Solution: **Using the formula: X + Y + XY/100

⇒ 20 + (-30) + 20 *-30 /100 = -16

This means there is a decrease of 16 %

**Q8. **A square is converted into a rectangle by increasing one of its sides by 5 % and reducing the other by 5 %. What will be the % change in the area of the two figures?

A. 0.5 % decrease

B. 0.5 % increase

C. 0.25 % increase

D. 0.25 % decrease

**Sol: Option D**

**Solution: **Let the side of the square = a

∴ Its area = a^{2}; When the square is being converted to a rectangle, the length becomes 1.05a and the width becomes 0.95a. ∴ New area = 1.05a × 0.95a = 0.9975a^{2}

Change in area = a decrease of 0.0025a^{2}

∴ % decrease in area =0.0025a^{2} * 100/a^{2}= 0.25 %

**Q9. **In an election there were two candidates P and S. The poll turnout was only 90 %. 500 of the given votes were declared invalid. P won 440 of X = 400 % of the total votes. Find the total number of eligible voters and the number of votes received by each of the candidates.

A. 5000,2200, 1800

B. 6000,1200,3800

C. 4000,1100,3500

D. 4500,2200,1000

**Sol: Option A**

**Solution: **Let the registered voters = X

P got 440/9 % of X = 4.4X/9

Since P got 400 votes more than S, S got 4.4X/9 – 400

Total votes registered = X = P + S + Invalid votes

X = 4.4 X/9 + (4.4 X/9 – 400)+ 500 ⇒ X = 8.8X/9 + 100

⇒ X = 4500. Since the poll turnout was only 90%, the total number of eligible voters = 100/90 * 4500 = 5000

Number of votes P got = 4.4/9 * 4500 = 2200

Number of votes S got = 2200 – 400 = 1800.

**Q10. **If the population of a town is 926100 and it has been growing annually at 5 %, what was the population 3 years ago?

A. 800,000

B. 600,000

C. 400,000

D. 450,000

**Sol: Option A**

Let the population be X

X * (100 + 5)^{3} / (100) ^{3} =926100; X * (105/ 100) * (105/100) * (105/100) = 926100

⇒ X * (21/20) * (21/20) * (21/20) = 926100

⇒ X = 926100 * (20/21) * (20/21) * (20/21) = 800,000