**Which of the following numbers is divisible by 2?**1. 1786532. 1648573. 1764854. 178560Answer : Option 4

A number is divisible by 2 if the last digit of the number is 0 or a multiple of 2. Therefore only 178560 is divisible by 2. So, answer is option 4.**Simplify the expression using BODMAS rule:: (3/2) of (4/7) {(10 × 3) – (8 × 2)}**1. 62. 123. 184. 14Answer : Option 2

Applying BODMAS rule = (3/2) of (4/7) {30 – 16} = (12/14) × 14=12

Therefore, the correct answer is option 2.**The product of 40 odd numbers is**1. even2. odd3. 6254. Can’t sayAnswer : Option 2

The product of 40 odd numbers will give an odd number. So answer is option 2.**The six digit number 54321A is divisible by 9 where A is a single digit whole number. Find A.**1. 02. 23. 44. 3Answer : Option 4

A number is divisible by 9, when the sum of its digits is divisible by 9. Here, 5 + 4 + 3 + 2 + 1 + A = 15 + A should be divisible by 9. Therefore, A = 3 gives 15+ 3 = 18 as the sum of digits, which is divisible by 9. So, answer is option 4.**The seven digit number 43567X is divisible by 3, where X is a single digit whole number. Find X.**1. 22. 53. 84. All of theseAnswer : Option 4

A number is divisible by 3 when sum of its digits is divisible by 3. Here, sum of digits = 4 + 3 + 5 + 6 + 7 + X = 25 + X. So, X can be 2, 5, 8 which gives the sum 27, 30 and 33 respectively. Therefore, X has 3 values here, for which the number is divisible by 3. So, the answer is option 4.

Must Read Problems on Numbers System Articles

- Problems on Numbers System: Level 01
- Problems on Numbers System : Level 02

**Find the greatest three number which is multiple of 7.**1. 9932. 9953. 9944. None of theseAnswer : Option 3

Greatest three digits number = 999. When 999 is divided by 7, the remainder will be 5. Required number= 999 – 5 = 994.**Find the greatest 6-digit number, which is a multiple of 12.**1. 9999802. 9999903. 9999844. None of theseAnswer: Option 4

Greatest six-digit number is 999999. Divide this number by 12 and get remainder as 3. Since the remainder is 3, if you subtract 3 from the number, the remaining number will be a multiple of 12. So the greatest such number will be 999999 – 3 =999996.**Find the smallest three number which is a multiple of 7.**1. 1032. 1053. 984. None of theseAnswer : Option 2

Smallest three digit number =100. Divide this number by 7 and get the remainder as 2. If you subtract 2 from the number the remaining number will be a multiple of 7, 100 - 2 = 98 which is two digit number. Now if we add 7 so that we get the smallest three digit number which is a multiple of 7. Required number = 98 + 7 = 105.**Simplify the expression using BODMAS rule (3/7) of (4/5) of 20 (25**^{2}- 24^{2})1. 3362. 1683. 844. None of theseAnswer : Option 1

(3/7) × (4/5) of 20 (625 - 576)⇒ (3/7) × (4/5) × 20 × 49 =336**Simplify the expression using BODMAS rule (105 + 206) - 550 ÷ 5**^{2}+ 101. 3992. 2893. 2984. 299Answer : Option 4

(105 + 206) - 550 ÷ 52 + 10

= 311 – 550 ÷ 25 + 10

= 311 – 22 + 10

= 289 + 10 = 299