Example 1: The product of 4 consecutive even numbers is always divisible by A. What is A?
The smallest possible 4 consecutive even numbers are: 2, 4, 6 and 8. The product of these four numbers is 2 × 4 × 6 × 8 = 384. So, any 4 consecutive numbers will always be divisible by 384.
Which least digit should replace the $ in the number 23$788, so that it becomes a multiple of 3.
As you know that if the sum of all the digits is divisible by 3, then the number is divisible by 3. Now sum of the given digits is 2 + 3 +$+ 7 + 8 + 8 = 28+ $. Now think the next multiple of 3 after 28 i.e. 30. This means you add 2 in this. The value of $ is 2.
Find the greatest three-digit number which is a multiple of 13.
Greatest three digit number is 999. When we divide 999 by 13, then 11 is the remainder. So, 999 – 11 = 988 is the answer.
Find the smallest 6-digit number, which is a multiple of 18.
To solve such question take the smallest six-digit number, which is 100000. Divide this number by 18 and get the remainder as 10. Here if you subtract 10 from the number, no doubt you will get a multiple of 18. But because you have already taken the smallest six-digit number, if you subtract anything from it, you will get a five-digit number. Think it otherwise, that instead of subtracting you add something.
Now what should be added to 10(the remainder) so that it becomes a multiple of 18? i.e. 18 – 10 = 8 ⇒ 8 should be added in the number i.e. 100000 + 8 = 100008 is the answer.
Find the sum of odd natural numbers up to 100.
Here we have 1 + 3 + 5 + ...... + 99 = (50 × 100/2) = 2500
What is the value of P, where P = 13 + 23 +......203 ?
You have to find the sum of first 20 perfect cubes. The formula of sum of cubes of 1st N Natural Numbers is to be applied. ∑203 =((20 × 21 )/ 2)2 = 44100.
How many total squares are there in 4 x 4 square?
The formula for number of squares in n x n square is ∑n2 and ∑n2 =(n(n+1)(2n+1)/6) Here n is 4. Putting n = 4, we get 30 as answer.
Find the smallest 8-digit number which is a multiple of 9
Smallest eight-digit number is 10000000, when we divide 10000000 by 9, then 1 is the remainder. So, 10000000 – 1 + 9 = 10000008 is the answer. (1 is subtracted to find the multiple of 9, as 1 is the remainder, but then 9 is added to get the smallest such eight-digit number, otherwise you were having a seven-digit number).
The sum of two numbers is 42. What could be the maximum possible product of those 2 numbers?
When the sum of two numbers is constant, then product of those two numbers is maximum, when those two numbers are as close to each other. As 21 + 21 = 42, so answer will be 21 × 21 = 441.
There are two numbers, such that one number is 6 more than the other number. If the total of two numbers is 18, find the product of those numbers.
x + x + 6 = 18, so x = 6, x + 6 = 12, product will be 6 × 12 = 72.
A piece of road is 3 km in length and we have to supply the lamp post, one post at each end and the difference between two consecutive lamp posts is 100 m. Find the total number of lampposts required.
As one lamppost is required at each end, so number of posts = (3000/100) + 1 = 31. One extra is added as there is one lamp post at the beginning as well as at the end..
In a class, every student shakes hand with every other student. If, the total number of students is 40, find the total number of handshakes that took place in the class.
The first student shakes hand with 39 other students, second student shake with 38 and so on. So, the total number of handshakes = 39 + 38 + 37........ + 1 =((39 × 40) / 2 ) =780
A gardener planted trees in rows and columns such that number of rows is five more than number of columns. If the total number of rows and column is 105, find the number of trees.
Let the number of columns = x. Number of rows = x + 5. According to the question, x + x + 5 = 105. So, 2x + 5 = 105 ⇒ x = 50. So, the number of columns = 50. Hence, the number of rows = 50 + 5 = 55. Hence, the number of trees = 55 × 50 = 2750.