Algebra forms an integral part of Quant section of various competitive examinations. Within algebra, a very important area from examination point of view is Progressions i.e. Arithmetic progression (A.P.) and Geometric Progression (G.P.). In this article, we will discuss mainly about Arithmetic mean (A.M.) and Geometric Mean (G.M.) as a lot of questions are asked from these two areas.

- Three numbers a, b & c are said to be in Arithmetic progression if b - a = c - b i.e. if the difference between the terms is same. This difference between the terms is called the common difference
- Eg. 5, 9, 13, 17, 21.... is an Arithmetic progression as the difference between the terms is same.

- As b - a = c - b => 2b = a + c or . Here 'b' is called the Arithmetic mean between 'a' and 'c'. In general, Arithmetic mean of the 'n' terms is equal to their average.

- Three numbers a, b and c are said to be in Geometric progression if i.e. if the ratio of the terms is same. This ratio of the terms is called the common ratio.
- Eg. 4, 16, 64, 256, 1024….. is a Geometric progression as the ratio of the terms is same.

- As => b
^{2}= ac or . Here 'b' is called the Geometric mean between 'a' and 'c'. In general, the geometric mean of 'n' numbers x_{1}, x_{2}, x_{3},.....x_{n}is given by

Relation between Arithmetic Mean and Geometric mean:

- The relation between Arithmetic mean and Geometric mean is very important. A lot of questions are asked based on this relation only.
Let us check the relation between the two.
- Let x and y are two positive real numbers. Then we have (x - y)
^{2}= 0=> x^{2}+y^{2}- 2xy = 0=> x^{2}+y^{2}- 2xy +4xy - 4xy = 0=> x^{2}+y^{2}+ 2xy - 4xy = 0=> x^{2}+y^{2}+ 2xy = 4xy=> (x + y)^{2}= 4xy

As we know** A.M. = G.M.**

We will apply the above result on three numbers 3a, 4b and (72 - 3a - 4b). We have selected these numbers as there sum will be a constant number and their product will have the terms required in the question.

Hence the maximum value of ab(72 - 3a - 4b) is 1152.

- This concept is useful when we have to find the minimum and maximum values of the expressions and we cannot do that by substituting the random values for the variables.
- As it is seen from the above example that if you put different values of 'a' and 'b' in the given expression then you will get different values and you cannot say which one is the maximum but by going through the result the maximum or the minimum value can be easily found. After solving a reasonable number of questions based on this, you will learn to take the appropriate values to get the desired answer.

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