A. Monday

B. Friday

C. Saturday

D. Thursday

We know that in 1600 years there will be 0 odd days.

So start counting from here. In 300 years after that, there will be 1 odd day.

10 May, 1999 implies that starting from the end of 1900, 98 years, 4 months and 10 days have elapsed since then. 98 years have 24 leap years and 74 non leap years leading to 122 odd days.

Dividing by 7 and checking remainder, net odd days = 3.

In the 4 months and 10 days of 1999, there are 31 days in Jan, 28 in Feb, 31 in March, and 30 in April.

Total days elapsed in 1999 = 31+28+31+30+10 = 130.

So net odd days = 4.

Adding up all the odd days we have got so far we get a total of 1 + 3 + 4 = 8.

Net odd day = 1, so May 10, 1999 was a Monday.

(The rule is that 0 odd days means the day is a Sunday, 1 means Monday, 2 means Tuesday and so on.)

A. Monday

B. Thursday

C. Saturday

D. Friday

May 10, 2001 will be a Thursday (1999 was a non-leap year so add one day and 2000 is a leap year, so add 2 odd days).

Now start counting the days from May 10, 2001 to 10–Dec–2001. Complete months in between are June, July, Aug, Sep, Oct, Nov – total days = 30 + 31 + 31 + 30 + 31 + 30 = 183 days. Plus 21 days in May and 10 days in Dec.

So total days = 214. Net odd days = 4. So 10–Dec–2001 will be 4 days after Thursday, which is Monday.

A. Saturday

B. Thursday

C. Tuesday

D. Friday

Up to first 1600 years no odd day.

From 1601 – 1900 1 odd day

From 1901 – 1946: 46 + 11 (leap)

= 57 – 56 (complete weeks) 1 odd day

First six months give = 6 odd days

July 3 = 3 odd days

Up to August 15 1 odd days

Total up to 15th August 10 odd days

Total no. of odd days 12 – 7 (complete week) = 5

Now counting from the beginning, 5 odd days, so India’s first Independence Day was on a Friday.

A. Friday

B. Thursday

C. Tuesday

D. Saturday

5.1. 1991– Saturday

∴5.1. 1992 was Sunday.

From 5.1.1992 to 3.3.1992, number of days = 26 + 29 + 3 = 58.

Hence number of odd days = 58/7 ⇒2

Day on 3.3.1992 was 2 days ahead of Sunday i.e. Tuesday.

A. Tuesday

B. Friday

C. Wednesday

D. Saturday

3.4.92 was Monday.

Number of days from 3.4.92 to 3.11.91

= 4 + 31 + 29 + 31 + 31 + 27 = 153.

Hence number of odd days = 153/7⇒6

Hence the day on 3.11.91 was 6 days behind Sunday i.e. Saturday.

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A. Tuesday

B. Saturday

C. Sunday

D. Thursday

2.1.97 was Thursday.

Number of days from 2.1.97 to 15.3.97

= 29 + 28 + 15 = 72.

Hence number of odd days = 72/7⇒2

Hence the day on 15.3.97 will be 2 days ahead of Thursday i.e. Saturday.

A. Friday

B. Sunday

C. Wednesday

D. Saturday

29.1.1950. Upto 1900, number of odd days = 1. From 1900 to 1949, there are 49 years in which 12 are leap years and 37 are normal years

Total number of odd days = (12 2) + (37 1) = 24 + 37 = 61 5.

Also 29 days of January will have 1 odd day. Hence the total number of days = 1 + 5 + 1 = 7

0.

Hence the day on this date i.e. 29.1.1950 was Sunday.

A. Friday

B. Thursday

C. Tuesday

D. Monday

Today is Tuesday. 1 yr, 68 days means 365 + 68 = 433 days.

Hence number of odd days = 433/7⇒6

Hence the day would be 6 days ahead of Tuesday i.e. Monday.

A. 2001

B. 1998

C. 1997

D. 2002

2 different years will have the same calendar if the total number of odd days from one year to the other is either 7 or multiple of 7.

So from 1986, if we go forward, odd days in 1987– 1, 1988 – 2, 1989 – 1, 1990 – 1, 1991 – 1, 1992 – 2, 1993 – 1, 1994 – 1, 1995 – 1, 1996 –2, 1997– 1. Total number of odd days up to 1997= 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 = 14.

Hence 1997 will have same calendar as 1986.

A. Monday

B. Thursday

C. Sunday

D. Friday

Each day of the week is repeated after 7 days. So, after 70 days, it will be Tuesday.∴ After 68 days, it will be Sunday.