1. Rashi spends 1/7th of his income on clothes,1/5th of the remaining on entertainment, 1/3rd of the remaining on books . If she still has Rs. 4800 with her, find her total income

A. 11025

B. 12025

C. 10500

D. 45256

Sol : Option C
Just concentrate on the remaining part at every step. Firstly she spends 1/7th of his income, implies he is left with 6/7th of his income. Then he spends 1/5th of that, means he saves 4/5th of that. After this she spends 1/3rd of the remaining, means he saves 2/3rd of that. In total she saves 2/3rd of 4/5th of 6/7th i.e. 2/3 × 4/5 × 6/7 of the total which is given to be 4800. Now 48/105 x = 4800 i.e. x = Rs. 10500.

2. Find the fractional equivalent of

A. 5209/16665

B. 5219/16665

C. 5239/16665

D. 5211/16665

Sol : Option A
As it is case of mixed recurring = (31257 – 3)/99990 = 31254/99990 = 5209/16665.

3. Find the fractional equivalent of

A. 1421/1111

B. 421/1111

C. 4211/1111

D. 419/1111

Sol : Option B
As it is case of pure recurring. = 3789/9999 = 421/1111.

4. Find the fractional equivalent of

A. 5111/9000

B. 6117/9000

C. 6119/9000

D. None of these

Sol : Option D = (6789-678)/9000 = 6111/9000.

5. After spending 3/4 of his income a man is left with Rs. 100.Find his total income.

A. 400

B. 200

C. 75

D. None of these

Sol : Option A
After spending 3/4th of the income, he will be left with 1/4th of the income and that is given to be Rs. 100, thus ¼ of income is 100. So income = 100 * 4/1 = 400

6. Ravi spends 2/9th of his income, then he spends3/7th of the remaining. If he still has Rs. 140 with him. Find his total income.

A. 315

B. 3150

C. 1175

D. 6130

Sol : Option A
7/9 of 4/7 of income = 140. 4/9 of income = 140 ⇒ income = 140 x 9/4 = 315

7. In a library 2/3 of books are in English and the remaining 300 are of Hindi. Find the total books in library

A. 400

B. 900

C. 275

D. None of these

Sol : Option B
2/3 of books are in English means remaining 1 – (2/3) = 1/3 are in Hindi which is equal to 300. So 1/3rd of total = 300 ⇒ Total books = 300 x 3 = 900.

8 Find the fractional equivalent of

A. 221/1650

B. 227/1650

C. 223/1650

D. None of these

Sol : Option C
As it is case of mixed recurring = (1351 – 13) /9900 = 1338/9900 = 223/1650.

9. Raju has some money. He gave 1/9 of it to his son Ramu and 2/3rd of remaining to his daughter Geeta. He still has Rs. 200 left. How much money he had initially.

A. 6400

B. 200

C. 675

D. None of these

Sol : Option C
As he gave 1/9 to his son Ramu so he is left with 1 – (1/9) = 8/9. Now out of 8/9 he gives 2/3 to his daughter so he is left with 1/3 of 8/9. so we will solve as follows: 8/9 of 1/3 of x = 200. x = 200 x 9 x 3/8 = 675.

10. Find the fractional equivalent of

A. 967/4995

B. 968/4995

C. 1968/4995

D. None of these

Sol : Option B
As it is case of mixed recurring = (1937-1)/9990 = 968/4995.